Thursday, November 7, 2013

Monash Cafeteria Questionnaire

Assignment 2 Monash Cafeteria Questionnaire 1. Statistics Q2 (1 to 5) NValid132 Missing0 specify2.40 median value2.00 Mode2 Q2 (1 to 5) Frequency percentageValid Percent cumulative Percent Valid13325.025.025.0 24030.330.355.3 33627.327.382.6 41914.414.497.0 543.03.0100.0 essential132100.0100.0 Based on the output above, it is estimated that the current corrupt behaviour is that majority of learners commonly take-away their purchases. This is demonstrated by ordinarily take-away response frequency of 30.3% and mode=2. analysis of random variable Q29 (1 to 7) Sum of Squ atomic bout 18sdfMean SquareFSig. Between Groups5.21641.3041.077.371 Within Groups153.7541271.211 impart158.970131 To adjust whether the pattern should be stratified on the primer of the purchase doings of students (Q2), the above ANOVA results are analyzed. The ANOVA dodge is used to determine whether the overall satisfaction aim of student will differ depending on the purchase behaviour root they belong to e.g. always take-away group. Since the Fstat value (1.077) is less(prenominal) than the Fcrit value (4,120,.05)=2.45, we break up that there is no difference amidst the overall satisfaction levels of students with contrary purchase behaviours. Therefore the try on should not be stratified based on this grouping. 2.
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The isotropy of people fit with the service quality can be represented by the following equation: p ?=(X+2)/(n+4) = 91/136 = 0.6691 = 67% satisfaction FrequencyPercentValid Percent cumulative Percent ValidSatisfie8967.467.467. 4 Unsatisf4332.632.6100.0 Total132100.0100! .0 Bound: p ?±2?(var(p ?)) NOTE: FPC is not required as the sample number (132) is less than 10% of the population number (approximately 40,000). p ?±2?((p ?(1-p ?))/(n+4)) p ?±2?((0.6691(1-0.6691))/136) B = 0.6691 ? 0.0807 This means we are 95% confident that the true proportion of students satisfied with...If you involve to labour a full essay, order it on our website: BestEssayCheap.com

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